InstallAware

Hello,

I need to get a fully qualified domain name (FQDN) if the computer is part of a domain, and a short computer name if not. Is it possible to do this using standard InstallAware commands?

Thanks,
Kostya

The Get System Settings command is your friend.

Have you looked at the following parameters:

Logged on Computer Name
Logged on Domain Name

John, thanks for your reply! The thing is that when I tried the Get System Settings command, if the computer is not part of a domain, then the domain name is not empty, but the same as the computer name. Combining the computer and domain name values I would get "COMPUTER1.COMPUTER1". Although, in this case I need the computer name only.

So, I expected that with the Logged on Domain Name parameter it returns an empty value in the described case. If it does not, then can I be sure that if the values ​​I get when using the Logged on Computer Name and Logged on Domain Name parameters are the same, then the computer is not part of a domain and the obtained domain name can simply be discarded? I'm just afraid I'm missing a more correct way to determine this.

John, since this still remains unclear, let me ask you straight: was it intended and is it correct that if my computer is not part of a domain, the following command returns the computer name?

In this case, I will have to determine the "not part of a domain" case somehow differently, since I don't find any command for this.

Oh I missed your reply from last week!

I have been able to confirm that this behavior is as designed - if the user hasn't been joined to a domain, the returned domain name is simply the name of the local device.

You could maybe compare the two values, and if they are equal - conclude that the computer has not been joined to a domain?

Got it, thanks for confirming! Yes, this way works.